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PLEASE HELP ME WITH PHYSICS!!!!!!What is the speed of the large cart after the collision? in m/s?

A small, 200 g cart is moving at 1.10 m/s on an air track when it collides with a larger, 1.00 kg cart at rest. After the collision, the small cart recoils at 0.850 m/s .

Momentum of smaller cart beginning + Momentum of larger cart beginning = Momentum of smaller cart after + Momentum of larger after
Let's take original direction of smaller cart positive.

(0.200kg)(1.10 m/s) + (1.00 kg)(0 m/s) = (0.200 kg)(- 0.850 m/s) + (1.00 kg)(V).
where V = speed of large cart after the collision.

V = [(0.200kg)(1.10 m/s) + (1.00 kg)(0 m/s) - (0.200 kg)(- 0.850 m/s)]/1.00 kg
V = 0.39 m/s answer

Hope this helps.

teddy boy

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